Our Lowest Common Multiple code in Python.
List Lowest Common Multiple Class File:
# A class
class findLCM:
# A constructor
def __init__(self, group):
self.set_of_numbers = []
for member in group:
self.set_of_numbers.append(member)
# Sort array in descending order
self.set_of_numbers.sort(reverse=True)
self.all_factors = []
self.index = 1
self.state_check = False
self.calc_result = 1
def findLCMFactors(self):
# Copy 'set_of_numbers' into 'arg_copy'
self.arg_copy = []
for number in self.set_of_numbers:
self.arg_copy.append(number)
# STEP 1:
# sort in descending order
self.arg_copy.sort(reverse=True)
while self.index <= self.arg_copy[0]:
self.state_check = False
for count in range(len(self.set_of_numbers)):
if self.set_of_numbers[count] % self.index == 0:
# STEP 3:
self.set_of_numbers[count] /= self.index
if self.state_check == False:
self.all_factors.append(self.index)
self.state_check = True # do not store the factor twice
# STEP 4:
if self.state_check: return self.findLCMFactors()
self.index += 1
return None
# Returns an array reference of the desired set of even numbers
def getLCM(self):
# STEP 2:
self.index = 2
self.findLCMFactors()
# iterate through and retrieve members
for factor in self.all_factors:
self.calc_result *= factor
return self.calc_resultMain Class:
#!/usr/bin/python
from LCM import findLCM
# Use the LCM module/class
group = [2, 3, 4]
lcm = findLCM(group)
answer = lcm.getLCM()
print("The L.C.M. of ", group, " is", answer, "\n")Try it out!
Elegance (0.0)
